![]() Or, think of a recursive approach to find the reversed list in a single pass.Think of an iterative approach to find the reversed list in a single pass.There are mainly two approaches to implementing it in C++: There can be two approaches to solving this problem, the following are the hints, try solving the problem by yourself, and then head over to the next section to find the solution and C++ code. For example, consider the following linked list:Īfter reversing the complete linked list we return the pointer to the new linked list as demonstrated in the figure: Here, we are provided with the pointer or reference to the head of a singly linked list, invert the list, and return the pointer or reference to the head of the new reversed linked list. In this way, the last node becomes the first node, the second-to-last node becomes the second node, and so on. Reversing the linked list implies reversing all the elements and we can do it by reversing all the links and making the next pointer point to the previous node. ![]() Let's understand the problem statement first to clearly understand what we are going to do. Head: A Linked List contains the pointer to the first link called a head pointer.Next: Every node of a linked list contains a link to the next link that is Next.Node: Each node stores data which is called an element.There are three components of a linked list: The linked list is the second most utilized data structure after arrays. The last node has a null pointer to indicate it is the end. Each link which is a pointer contains a connection to another node. Let’s get Kraken! What is a Linked List in C++?Ī linked list is a sequence of links that contain elements connected using pointers. In this article, we will learn how to reverse a linked list in C++. We use linked lists to maintain a directory of names, dynamic allocation of memory, and create an implementation of essential data structures like stacks and queues, and whatnot. Many of you must be familiar with the application of a linked list in the real world and its importance.
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